Quet’s Rational Iteration Denominator Recurrence
Abstract
The reduced denominators of Quet’s rational iteration satisfy his recurrence.
Definition 1.1 (Pair-recurrence numerator).
Formalization. D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.num (✓ std3).
Source. Repository-derived.
Acknowledgement. Leroy Quet; N. J. A. Sloane (2003). OEIS A079278, denominators of the rational iteration b(n) = b(n-1) + 1/(1 + 1/b(n-1)). URL: https://oeis.org/A079278.
Commentary.
The auxiliary numerator starts with num(0)=0 and num(1)=1. Each later value is the preceding numerator multiplied by that numerator plus twice the preceding denominator.
Definition 1.2 (Pair-recurrence denominator).
Formalization. D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.den (✓ std3).
Source. Repository-derived.
Acknowledgement. Leroy Quet; N. J. A. Sloane (2003). OEIS A079278, denominators of the rational iteration b(n) = b(n-1) + 1/(1 + 1/b(n-1)). URL: https://oeis.org/A079278.
Commentary.
The denominator starts with den(0)=den(1)=1. Each later value is the preceding denominator multiplied by the sum of the preceding numerator and denominator.
Definition 1.3 (Quet’s rational iteration).
Formalization. D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.b (✓ std3).
Citation. Leroy Quet; N. J. A. Sloane (2003). OEIS A079278, denominators of the rational iteration b(n) = b(n-1) + 1/(1 + 1/b(n-1)). URL: https://oeis.org/A079278.
Commentary.
The rational sequence is extended by b(0)=0 and begins with b(1)=1. At every later index it adds one divided by one plus the reciprocal of the preceding value.
Theorem 1.4 (Quet’s denominator recurrence).
Proof. Machine-checked in Lean as D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.result (✓ std3). ∎
Resolves. Problems/oeis-a079278-quet-rational-iteration-denominator-recurrence (proved) by D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.result.
Source. Repository-derived.
Acknowledgement. Leroy Quet; N. J. A. Sloane (2003). OEIS A079278, denominators of the rational iteration b(n) = b(n-1) + 1/(1 + 1/b(n-1)). URL: https://oeis.org/A079278.
Commentary.
For every m at least two, the square of the reduced denominator of b(m-1) divides the cube of the reduced denominator of b(m), and the reduced denominator of b(m+1) satisfies Quet’s formula. The divisibility clause makes the natural-number quotient exact. The reduced-form bridge identifies these denominators with the integer pair recurrence before the numerator recurrence yields the equation.
References
- Truth anchor:
D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.b - Truth anchor:
D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.den - Truth anchor:
D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.num - Truth anchor:
D5/S1/Recurrence/Residue/QuetRationalIterationDenominator.result