Largest-prime period iteration
Abstract
The largest prime above five loses exactly its original Fibonacci depth at each period iteration.
Theorem 1.1 (Exact depth loss for every positive modulus).
Lean statement: D5/S3/Arith/Primes/GoldenLargestPrimePeriodIteration.golden_largest_prime_period_iteration
Proof. Machine-checked in Lean as D5/S3/Arith/Primes/GoldenLargestPrimePeriodIteration.golden_largest_prime_period_iteration (✓ std3). ∎
Source. Repository-derived.
Commentary.
Let m be positive and let P greater than five be its largest prime divisor. Write a for the P-adic valuation of m and h_P for the P-adic valuation of the Fibonacci number at the first positive index divisible by P. For every n at least zero, the P-adic valuation of the n-th iterate of the Fibonacci matrix period is a minus n times h_P, truncated at zero. The prime P divides that iterate exactly when n is less than the ceiling of a divided by h_P. Thus P first disappears at that ceiling and never returns. Every positive fixed point of the period function has no prime divisor greater than five. If the periods of m and m squared agree, then h_P is at least twice a. The theorem does not classify the remaining fixed points or bound the total time until an iterate becomes fixed.
References
- Truth anchor:
D5/S3/Arith/Primes/GoldenLargestPrimePeriodIteration.golden_largest_prime_period_iteration - Dependency: D5/S3/Arith/GoldenFibonacciModulusPeriod
- Dependency: D5/S3/Arith/GoldenPrimePowerOrder
- Dependency: D5/S3/Arith/Primes/GoldenPrimePowerMatrixPeriod