Quotient Integral Budget
Abstract
Actual quotient residual blocks have separate head and logarithmic tail payments before infinite integral exchange.
Let K(y) be the finite prefix of k(n) over positive integers n<=floor(y), G(y)=Aylog(y)-Dy and R=K-G. The real coefficients A,D are arbitrary. Assume independent C,mu>=0, 0<=k(n)<=Clog(n) for every n>=1, and |R(y)|<=mu*(1+log(y)) for every y>=1. The coefficient assumptions imply k(1)=0. On 0<y<1 the actual residual is Dy-Ay*log(y).
For x>1 use the existing Robin weight w(t)=(1+log(t))/(t^2log(t)^2) and W(x)=(1+log(x))/log(x)^2. Define Q(x,m) as the integral on t>x of |R(t/m)-R(t/(m+1))|w(t). This absolute value is taken inside the integral. Put a2=C+|A|, a1=C+2|A|(1+log(2))+2*|D|+2mu and a0=4mu.
Theorem 1.1 (The actual residual blocks are integrable with separate first and quadratic logarithmic budgets).
Lean statement: D5/S3/Arith/Robin/QuotientIntegralBudget.quotientIntegralProducer
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/QuotientIntegralBudget.quotientIntegralProducer (✓ std3). ∎
Source. Repository-derived.
Commentary.
For every x>1 the actual weighted absolute block is integrable for every m>=1. The first block obeys Q(x,1)<=W(x)(mu(3+2log(2))+|D|+|A|log(2)). Every m>=2 obeys Q(x,m)<=W(x)/m^2(a2log(m)^2+a1*log(m)+a0).
With c=m/(m+1), each finite prefix jump has support [n,n/c). The low domain is enlarged to 1/m<=y<=m and its finite jump sum is integrated before any infinite exchange. Exact jump masses and a smooth log-product majorant pay this domain. The centered residual envelope pays y>m, retaining the actual residual instead of separately integrating unsigned K and G on the tail.
Theorem 1.2 (Every strict tail has its explicit logarithmic payment).
Lean statement: D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_logarithmic_tail
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_logarithmic_tail (✓ std3). ∎
Source. Repository-derived.
Commentary.
Let B>=0 and assume the explicit inequality |H(m)|<=Bm/log(m)^4 for every m>=2. For every M>=2 the strict tail sum over m>M of |H(m)|Q(x,m) is at most BW(x)(a2/log(M)+a1/(2log(M)^2)+a0/(3log(M)^3)). The strict enumeration is m=n+M+1, and reciprocal-log integral tests pay the three terms with their exact factors 1, 1/2 and 1/3.
Theorem 1.3 (The signed series has integrable blocks and a complete norm budget).
Lean statement: D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_signed_integral_budget
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_signed_integral_budget (✓ std3). ∎
Source. Repository-derived.
Commentary.
For the same hypotheses define F(m,t)=H(m)*(R(t/m)-R(t/(m+1)))*w(t). Every positive-index F(m) is integrable on t>x, and the integral of its pointwise norm equals |H(m)|*Q(x,m). The sequence of these norm integrals is summable. H(1) is unrestricted and its norm integral is at most |H(1)| times the separate first-block budget. Every strict norm tail has the preceding explicit bound.
These integrable blocks and summable integrals of their pointwise norms supply the premises of Mathlib’s integral_tsum_of_summable_integral_norm. That existing Fubini result is the downstream supplier. The coefficient and residual envelopes do not prove the independent H growth hypothesis, the complete Robin inequality or the Riemann hypothesis.
References
- Truth anchor:
D5/S3/Arith/Robin/QuotientIntegralBudget.quotientIntegralProducer - Truth anchor:
D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_logarithmic_tail - Truth anchor:
D5/S3/Arith/Robin/QuotientIntegralBudget.quotient_signed_integral_budget - Dependency: D5/S3/Arith/Robin/MellinWeightedVariation