Equality Graphs for the Two-Thirds Bound
Abstract
The equality characterization is Theorem 2.9 of Iain Beaton and Ben Cameron, A Tight Upper Bound on the Average Order of Dominating Sets of a Graph, arXiv:2208.10475. A graph is star-like precisely when every vertex is a leaf or a stem having one or two leaf neighbours.
Theorem 1.1 (Strictness outside stem blocks).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.residual_total_lt_of_core_nonempty
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.residual_total_lt_of_core_nonempty (✓ std3). ∎
Source. Repository-derived.
Commentary.
If an isolate-free graph has a vertex in no stem block, the residual critical-incidence estimate is strict.
Theorem 1.2 (Strictness for three leaves).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.active_block_total_lt_of_large_stem
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.active_block_total_lt_of_large_stem (✓ std3). ∎
Source. Repository-derived.
Commentary.
If a stem has at least three leaf neighbours, the active-block critical-incidence estimate is strict.
Theorem 1.3 (Equality of incidence counts).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.critical_total_eq_of_avd_eq
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.critical_total_eq_of_avd_eq (✓ std3). ∎
Source. Repository-derived.
Commentary.
Equality in the two-thirds average bound gives equality of the total critical and omitted incidence counts.
Theorem 1.4 (Equality forces a star-like graph).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.starLike_of_avd_eq_two_thirds
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.starLike_of_avd_eq_two_thirds (✓ std3). ∎
Source. Repository-derived.
Commentary.
An isolate-free graph attaining average 2|V(G)|/3 is star-like. A vertex outside all stem blocks or a stem with three leaves would give a strict incidence inequality.
Theorem 1.5 (Star-like graphs attain equality).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_of_starLike
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_of_starLike (✓ std3). ∎
Source. Repository-derived.
Commentary.
Every finite star-like graph without isolated vertices has dominating-set average equal to two thirds of its order.
Theorem 1.6 (Beaton–Cameron equality characterization).
Lean statement: D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_iff_starLike
Proof. Machine-checked in Lean as D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_iff_starLike (✓ std3). ∎
Source. Repository-derived.
Commentary.
For a finite graph without isolated vertices, the average cardinality of dominating sets equals two thirds of the graph order if and only if every vertex is a leaf or a stem with one or two leaf neighbours.
References
- Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.active_block_total_lt_of_large_stem - Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_iff_starLike - Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.avd_eq_two_thirds_of_starLike - Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.critical_total_eq_of_avd_eq - Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.residual_total_lt_of_core_nonempty - Truth anchor:
D5/S3/Combinatorics/Graph/DominatingSetAverageBoundEquality.starLike_of_avd_eq_two_thirds - Dependency: D5/S3/Combinatorics/Graph/DominatingSetAverageBound