The Fibonacci enumeration
Abstract
The numbers of simple permutations in C of sizes zero, one and two are respectively one, one and two. For every n at least three, the number of simple permutations of size n sortable by two parallel pop stacks with bypass is F_(2n-5) minus the remainder of n on division by two, where F_0 = 0 and F_1 = 1.
Theorem 1.1 (The Fibonacci enumeration).
Lean statement: D5/S3/Combinatorics/PopStack/PopStackSimple.result
Proof. Machine-checked in Lean as D5/S3/Combinatorics/PopStack/PopStackSimple.result (✓ std3). ∎
Resolves. Problems/cioni-ferrari-smith-pop-stack-simple (proved) by D5/S3/Combinatorics/PopStack/PopStackSimple.result.
Source. Repository-derived.
Acknowledgement. Lapo Cioni, Luca Ferrari, Rebecca Smith (2025). Sorting permutations using a pop stack with a bypass. DOI: 10.1016/j.disc.2025.114964. URL: https://arxiv.org/abs/2503.08285v1.
Commentary.
The numbers of simple permutations in C of sizes zero, one and two are respectively one, one and two. For every n at least three, the number of simple permutations of size n sortable by two parallel pop stacks with bypass is F_(2n-5) minus the remainder of n on division by two, where F_0 = 0 and F_1 = 1.
References
- Truth anchor:
D5/S3/Combinatorics/PopStack/PopStackSimple.result - Dependency: D5/S3/Combinatorics/PopStack/PopStackContinuationAvoidance
- Dependency: D5/S3/Combinatorics/PopStack/PopStackContinuationReflection
- Dependency: D5/S3/Combinatorics/PopStack/PopStackThirdEquivalence