bibkey: memarzadeh2016minimum authors: Laleh Memarzadeh; Stefano Mancini year: 2016 title: “Minimum output entropy of a non-Gaussian quantum channel” doi: 10.1103/PhysRevA.94.022341 url: https://arxiv.org/abs/1605.04525v1 claim: “Conjecture 1: truncated loss-dephasing minimum output entropy is attained by a binomial or kappa state.” strata_touched:
- D5/S3/Quantum/QuantumChannels/TruncatedLossDephasingOptimizerRefutation license: citation-only triage: anchor
Truncated loss-dephasing minimum output entropy
Conjecture 1, section IV, arXiv v1 PDF p. 4:
In a truncated Hilbert space of dimension K+1, the minimal output entropy of the quantum channel (3) is achieved either by binomial states of Eq.(14) or by states |κ_α⟩ of Eq. (11), depending on the values of ε and t.
The defining channel equations (1)–(7), pp. 1–2, give
Equation (9) fixes the input energy, . Equation (11) defines . Equation (14) defines the binomial amplitudes ; the energy condition is , and the allowed truncation sizes satisfy .
The Lean encoding uses matrices on Fin (K+1), the Kraus equations above,
and positive semidefinite trace-one inputs with number expectation N. For K ≥ 1,
N ∈ [0,K], ε ∈ [0,1], and t ≥ 0, the claim says that some binomial or κ candidate
has output entropy no greater than every admissible input. Its negation is proved.
The spectral entropy uses natural logarithms, whereas the paper uses base two;
multiplication by the positive constant 1/log(2) preserves the ordering.
The definition extends entropy to all raw matrices by assigning zero to
non-Hermitian matrices; the matrices used in the refutation are Hermitian and positive.
The counterexample uses K=2, N=3/2, ε=6/7, t=(7/2)log(2), and ψ=(|1⟩+|2⟩)/√2. Its output spectrum has a value above 1/2 and a value below 1/8. The only admissible binomial candidate is M=2, μ=3/4; its output spectrum and every κ candidate’s output spectrum lie strictly between 1/8 and 1/2. Their common trace is one. Strict three-coordinate majorization gives smaller entropy for ψ than for every candidate; no assertion that ψ is the global minimizer is made.
The displayed κ output in section III uses in its off-diagonal coefficient. The defining Kraus equations give instead. The encoding follows the Kraus equations and derives the K=2 off-diagonal coefficient √3/32768 at the counterexample parameters.
Verified locator
- DOI: https://doi.org/10.1103/PhysRevA.94.022341
- URL: https://arxiv.org/abs/1605.04525v1
- PDF: https://arxiv.org/pdf/1605.04525v1 (channel pp. 1–2; Conjecture 1 p. 4).