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slug: erdos-197-order-gadget-all-residues bibkey: kasel2026erdos197 doi: null url: https://arxiv.org/abs/2609.02939v1 triage: theorem motivation_gids:

  • D5/S3/Combinatorics/ErdosGrahamOrderGadget.result

The Order Gadget of the Erdős–Graham Two-Set Problem Is Infeasible at Every Scale

Problem

William Kasel, Structural rigidity in the Erdős–Graham two-set permutation problem, arXiv:2609.02939v1, Remark 30:

The full order gadget is nevertheless conjectured infeasible at every M ≥ 16 (machine-verified for 16 ≤ M ≤ 200 and M = 512, Proposition 18); at every swept scale with M ≢ 0 (mod 8) the C3 core was satisfiable, and other attack subsets were observed computationally to take over (Proposition 19); a proof beyond the swept scales would need per-residue analogues of Theorems 27–28 built from the same flood toolkit.

The order gadget OG(M) of Definition 15 asks for a linear order of (M, 2M] in which no in-block three-term arithmetic progression is monotone and, for x ∈ {15, 16} and 1 ≤ j ≤ x/2, the guard 2M + 2j − x precedes the bottom M + j.

Motivation

The frozen theorem D5/S3/Combinatorics/ErdosGrahamOrderGadget.result proves the conjecture: for every M ≥ 16 the gadget is infeasible. The paper needed only the residue class M ≡ 0 (mod 8), which contains the dyadic scales, to eliminate the canonical partition for Erdős Problem 197. The all-scale statement is a local obstruction usable by any block-based attack on that problem, and it settles the remaining seven residue classes.

Gap

Issue 9614 records the screen made before the work. The erdosproblems.com problem page, forum thread and proof-claims page for Problem 197 show no proof claims and nobody working on it; the author’s repository still lists the full conjecture as open; google-deepmind/formal-conjectures states only the parent problem; searches by title, arXiv number and “order gadget” found no later proof. Nothing under Problems/, D5/ or Library/, and no entry of the three screening records, concerns this paper.

Route

Write b_j = M + j, t_i = 2M − i, h = 3M/2. AP-freeness gives the four midpoint rules of the paper, from which follow its zigzag lemma (on any ladder of a fixed difference, one parity class of rungs precedes all its neighbours), phase dichotomy, and the phase-independent flood: for a center q and a class C of step g ∈ {2, 4} with q ≡ C + g/2 (mod g), one relation q ≺ v with v in the admissible mirror range forces q ≺ w for every class member w in that range.

Even M. Use the four guards t_11 ≺ b_2, t_7 ≺ b_4, t_14 ≺ b_1, t_10 ≺ b_3. Split on the order of the adjacent tops t_11, t_10; this fixes which parity leads on the difference-one ladder. In each branch let c be the largest integer below h in a fixed class modulo four and d = c + 2. A difference-two flood from c reaches a top, a guard carries it to a bottom, and a difference-four flood from c seeded at that bottom reaches d: c ≺ d. The same four moves from d, with the other two guards, give d ≺ c.

Odd M. The same scheme with the guards t_13 ≺ b_1, t_9 ≺ b_3, t_12 ≺ b_2, t_8 ≺ b_4, splitting on t_13, t_12, with centres c = M + j + 2 + 4⌊(M − 2j − 5)/8⌋ and d = c + 2.

In both parities every seed distance, radius and mirror is an explicit function of M, valid for all M ≥ 16 (even) and M ≥ 17 (odd) with no exceptional small cases. The theorem follows because each four-guard set is a subset of the fifteen guards of OG(M).

Falsifier

The statement would fail if some scale admitted an AP-free order satisfying either four-guard set. It would also fail to be the paper’s statement if the guards were read with j ranging up to x instead of x/2, or with the block closed at M; the definitions in the formal module follow Definition 15 literally, with the block M + 1, …, 2M.

Evidence

An independent SAT encoding (explicit transitivity, CaDiCaL) reproduces Proposition 18 and the residue behaviour of the three-guard core at 16 ≤ M ≤ 40, and finds each four-guard set inconsistent with AP-freeness at every M from 16 to 168 of the matching parity and at 200, 201, 256 and 257. No guard set of size at most four is inconsistent at every M from 24 to 168 at once, which is why the argument splits by parity. Every intermediate relation of both hand proofs was checked mechanically at every even M from 16 to 120 and every odd M from 17 to 121, each flood in both phases of its ladder and without the guards installed.

Triage

theorem; Tier 1 named open conjecture from a 2026 paper, preregistered in issue 9614 before the work. The computational use is none: the delivered statement is universally quantified over every M ≥ 16, and no declaration is a bounded enumeration, a checker, a numeric reduction or a certified instance.

ASSUMED-UNVERIFIED

The literature screen is bounded to the sources named above; citation indices were not exhaustively reachable, so no worldwide priority claim is made. The result settles Kasel’s conjecture on the order gadget; it does not settle Erdős Problem 197 itself.