slug: oeis-a100952-log-bounded-semiprime-partition-refutation bibkey: vospost2004a100952 doi: null url: https://oeis.org/A100952 triage: theorem motivation_gids:
- D5/S3/Arith/Congruence/VosPostLogBoundedSemiprimePartitionRefutation
Refutation of the A100952 log-bounded semiprime-partition conjecture
Problem
OEIS A100952, NAME (verbatim):
Numbers that cannot be written as p*q+r with three distinct primes p, q and r.
COMMENT (verbatim; Jonathan Vos Post, Nov 25 2004):
A weaker conjecture: every integer greater than 60 (or some larger value based on further search) may be partitioned into a prime p and a semiprime qr, where the prime p is bounded by log(min(q,r)). Chen (1978) showed that all sufficiently large even numbers are the sum of a prime and the product of at most two primes. Zumkeller’s conjecture effectively extends this from “even” to both even and odd integers. - Jonathan Vos Post, Nov 25 2004
AUTHOR (verbatim):
Reinhard Zumkeller, Nov 23 2004
The literal refuted statement is
exists B : Nat, 60 <= B and forall m : Nat, B < m -> Rep m, where
Rep m means that there exist natural primes p, q, and r satisfying
m = p + q*r and
(p : Real) <= Real.log ((min q r : Nat) : Real). Here Real.log is the
natural logarithm, equal factors q = r are allowed, and no distinctness
condition is imposed. The refutation therefore covers every stricter reading
that requires the three primes to be distinct. It does not resolve the
completeness conjecture for A100952 or Seidov’s p*q-r conjecture.
Motivation
The OEIS comment asks for one threshold after which every integer has a log-bounded prime-plus-semiprime representation. A symbolic obstruction for the entire residue class five modulo six disproves every possible threshold, including thresholds larger than sixty.
Gap
Preregistration issue #7620 and its probe report record searches dated
September 14, 2026. The OEIS aggregate history records a 2015 edit from ln
to log and contains no proof or refutation. Individual early revision pages
returned HTTP 403 and are ASSUMED-UNVERIFIED. An exact arXiv search returned
0 results. OpenAlex autocomplete returned 0 results, its /works endpoint
returned HTTP 429, and its web page returned HTTP 403; the latter two surfaces
are ASSUMED-UNVERIFIED. Crossref returned 0 results, MathOverflow returned 0
results, and a GitHub exact-phrase search returned 0 results.
PlanetMath material about Chen’s theorem and Zumkeller’s conjecture supplies
background but does not dominate the logarithmic bound. An external AI
discussion dated May 9, 2026 had a redirecting full-text link and is
ASSUMED-UNVERIFIED; its abstract concerns only finiteness. Chen’s 1978
theorem has no logarithmic bound and does not cover odd integers. These are
bounded search surfaces, not an exhaustive literature result, and no priority
claim is made.
Route
For m = 6*t+5, suppose a representation exists.
- If
min(q,r) <= 3, then primality gives2 <= p, whileReal.log_lt_sub_one_of_posgiveslog(min(q,r)) < min(q,r)-1 <= 2, contradicting the logarithmic bound. Henceq > 3andr > 3. - The primes
qandrare odd. Sincemis odd andq*ris odd, parity forces the primepto equal two. - The equation becomes
q*r = 6*t+3 = 3*(2*t+1). Euclid’s lemma for primes forcesq = 3orr = 3, contradicting the first step. - Given any proposed threshold
B, the valuem = 6*(B+10)+5is aboveBand belongs to the forbidden residue class, so the eventual claim fails.
Falsifier
The refutation would fail if Real.log_lt_sub_one_of_pos did not yield the
strict bound used for min(q,r) in the range from two through three, if a
prime above three could be even, if primality did not convert divisibility by
three into equality with three, or if 6*(B+10)+5 were not above every
proposed natural threshold B.
Evidence
- Lean module:
D5/S3/Arith/Congruence/VosPostLogBoundedSemiprimePartitionRefutation.lean. - Main theorem:
result : not claim, with exactly the std3 axiomspropext,Classical.choice, andQuot.sound. - On the stamped hot tree, the kernel run took 11.53 seconds wall time, reported 52.8 milliseconds of cumulative type checking, and used 2,156,838,912 bytes maximum resident set size.
- The orchestrator checked the 3,323 integers
mwith61 <= m <= 20000andmcongruent to five modulo six; 0 were representable. - On
(60, 2000], the orchestrator found 197 representable integers; the first eight were 123, 145, 171, 189, 211, 223, 249, and 255. - The search seat checked all 499,970 odd integers with
61 <= m <= 10^6; 108,602 were representable, while all 166,656 values congruent to five modulo six failed. - The probe repeated the range through 20,000 and obtained the same readings.
The bounded searches are observations and do not carry the theorem. The Lean proof establishes the infinite residue-class obstruction symbolically.
Triage
theorem. The formal result refutes the log-bounded sub-conjecture by proving
that no threshold works. It makes no claim about the completeness of A100952,
Seidov’s conjecture, or priority.
The module is classified utility: none. The declarations Rep and claim
are definitions. The theorem result is a symbolic refutation by an infinite
family using a real-log estimate and residue classification; none of
bounded-enumeration, checker, numeric-reduction, or
certified-instance applies. The open-problem resolution kind is Refuted.
ASSUMED-UNVERIFIED
The individual early OEIS revision pages, the OpenAlex /works endpoint and
web page, and the full text of the external May 9, 2026 discussion were not
retrieved for the reasons recorded above. The orchestrator, search-seat, and
probe bounded-search readings were supplied by issue #7620 and were not
recomputed by this implementation seat. No arXiv-complete, OpenAlex-complete,
or priority claim is made.