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Metadata
slug: roch-i-carceller-tavakoli-2025-energy-restricted-unitary-encoding
bibkey: rochicarcellertavakoli2025energyentanglement
doi: 10.1088/2058-9565/ae4d80
url: https://arxiv.org/abs/2510.27473v1
triage: theorem
motivation_gids:
  - D5/S3/Quantum/Entanglement/EnergyRestrictedUnitaryEncodingRefutation.result

Unitary entanglement-assisted encoding beats every unassisted strategy in an energy-restricted four-message task

Problem

C. Roch i Carceller and A. Tavakoli, The role of entanglement in energy-restricted communication and randomness generation, arXiv:2510.27473v1, Quantum Sci. Technol. 11, 025020 (2026), study prepare-and-measure communication whose only restriction is the vacuum component of the message, ⟨0|τ_x^C|0⟩ ≥ 1 − ω (Eq. (3)).

  • Result 4. For the probabilistic transmission of a bit, unitary encodings of a shared pure entangled state give no advantage over unassisted quantum communication with shared randomness.
  • The question (§VI, p. 9): “Whether unitary encoding remains resourceless for general tasks is an interesting open problem.”

The verbatim statements are in the literature note.

Issue #17895 fixes the reading:

  • resourceless for general tasks means that, for every linear task and every energy 0 ≤ ω < 1/2, each unitary-encoded entanglement-assisted value is matched by an unassisted value;
  • at ω ≥ 1/2 the question is settled by dense coding with a maximally entangled pair.

This statement is refuted: unitary encoding is a resource for a four-message task at ω = 288/625.

Motivation

The source shows that entanglement helps energy-restricted communication only through non-unitary encodings for one bit. D’Avino, Senno, Alimuddin and Acín (arXiv:2510.27559) prove the same for any two-input task with ω < 1/2. The question asks whether the intuition from dense coding fails for every task under an energy restriction, or only for two inputs.

Gap

Issue #17895 records the literature check before any Lean:

  • arXiv v1 is the only version, and the journal version keeps the question;
  • the companion arXiv:2510.27559v3 restricts to two inputs, and its theorem builds a common ground state for two encoded states;
  • the later arXiv:2608.27357, 2509.06726 and 2608.09667, read in full text, do not treat unitary encoding beyond two inputs;
  • Naixu-Guo/quantum-open-problems and the repository had no record.

not-found-in-searched-scope.

Route

  1. Protocol. Alice and Bob share Ψ = (4/5)|00⟩ + (3/5)|11⟩.
    • Alice encodes x = (u, v) by U_{uv} = Z^u R Z^v, with R = (1/5)[[4, −3], [3, 4]] and Z = diag(1, −1).
    • Every message marginal has vacuum component 337/625, so the energy is ω = 288/625 < 1/2.
    • Bob measures the orthonormal basis m_{uv} = (1/2)(1, −(−1)^v, (−1)^u, (−1)^{u+v}). Each overlap is 49/50, so the average success is 2401/2500.
  2. Pure-state inequality, in every Hilbert space. For unit vectors ψ and |0⟩ and an effect 0 ≤ E ≤ 1: ⟨ψ, Eψ⟩ − ⟨0, E0⟩ ≤ √(1 − |⟨0|ψ⟩|²).
    • Choose the phase of ψ so that a = ⟨0|ψ⟩ ≥ 0, and put u = ψ + |0⟩ and v = ψ − |0⟩. The difference equals Re⟨u, Ev⟩ and also −Re⟨u, (1 − E)v⟩.
    • Cauchy–Schwarz for the positive forms of E and of 1 − E bounds its square by both ⟨u, Eu⟩⟨v, Ev⟩ and ⟨u, (1 − E)u⟩⟨v, (1 − E)v⟩. Together these give at most ‖u‖‖v‖/2 = √(1 − a²).
  3. Unassisted bound. A message is an ensemble of unit vectors with weights summing to 1, the ensemble decomposition of its density operator.
    • Sum the pure inequality over the four messages, with Σ_x E_x = 1, and average over the ensembles and the shared randomness.
    • The averaging bound Σ_j w_j √t_j ≤ √(Σ_j w_j t_j), which is Cauchy–Schwarz for the sequences √w_j and √(w_j t_j), then shows that every unassisted strategy at energy ω succeeds with probability at most 1/4 + √ω. The message space has any dimension.
  4. Conclusion. √(288/625) < 17/25, so every unassisted value is below 93/100 < 2401/2500.

Falsifier

The refutation would not answer the question if:

  • the module’s strategies or energies differed from Eqs. (1)–(5);
  • its unassisted side omitted shared randomness or mixed messages;
  • its task were not a linear task of the source’s form.

The module quantifies over every finite task and every 0 ≤ ω < 1/2. Its unassisted strategies have:

  • an arbitrary complex Hilbert space for the message, with a unit vacuum vector;
  • shared randomness over an arbitrary index type with weights summing to 1;
  • messages given by ensembles of unit vectors. Every density operator has such a decomposition (its spectral decomposition), and every ensemble defines one;
  • POVMs of positive bounded operators summing to the identity;
  • the averaged energy restriction of Eq. (5).

This is the source’s QC model, Eqs. (4)–(5), which fixes no message dimension. The unitary strategies are finite-dimensional, which only weakens the claim.

Evidence

The canonical source is D5/S3/Quantum/Entanglement/EnergyRestrictedUnitaryEncodingRefutation.lean (506 lines).

  • It defines IsPOVM, UnitaryStrategy, encoded, unitaryProb, unitaryVacuum, QCStrategy, qcProb, qcVacuum, taskValue and claim, and proves result : ¬ claim.
  • It reuses frozen finite-dimensional matrix results for the protocol, and Mathlib’s inner product spaces and operator order for the unassisted side. No frozen owner is changed.
  • It uses only the standard axioms propext, Classical.choice and Quot.sound; no sorry, native_decide, or new axiom.
  • The escape registrations: result is the designated refutation result of the utility header and is exempt. The module has no other public theorem.

Frozen state: Golden/Frozen/state/D5/S3/Quantum/Entanglement/EnergyRestrictedUnitaryEncodingRefutation.lean.json, statement sha256:d9e9b1fdef83e9af30768b0a86ded67b0f227ac8114b455b7a22e90443787c58.

Declaration statements:

  • result: sha256:131df8981c442c115d95dbd2b558c08f0b1c26deb2621ffc905a794161ba45dd;
  • claim: sha256:ad777371d7368117ec5e109036a9b372610f2fdc9502481ff97fd5d8572f68e7.

Triage

Tier 1 question of a 2025 paper, preregistered in issue #17895 before any Lean. The preregistration revision on #17895 widens the unassisted class to the source’s model. theorem; resolution refuted.

declarationproof_shapeescape_witnessadmission_basis
resultbind-onlynone: after inlining, the protocol identities are finite computations, and the bound is an instantiation of Cauchy–Schwarz for positive operators and Hölder’s inequality for sums with exponents 2 and 2, followed by normalizationopen-problem-resolution
the protocol, effect-bound and Jensen helpers (private)bind-only (consumed on the proof path of result)noneconsumed helpers

Every other public declaration is a definition used by a public statement. The bind-only form is admitted under the open-problem-resolution basis of CLAUDE.md §3.2; no escape witness is claimed. The refutation is a certified instance with basis refutes. There is no digestion atom.

What the settlement shows

Refuted by result: at ω = 288/625 < 1/2, a unitary-encoded entanglement-assisted strategy reaches 2401/2500 in four-message discrimination, while every unassisted strategy, with messages in any Hilbert space and arbitrary discrete shared randomness, stays below 93/100.

Computed, not formalized (orchestrator, exact, recorded in #17895): the four message marginals (1/625)[[337, ±84], [±84, 288]], Bob’s constant marginal diag(16/25, 9/25), and the success matrix with diagonal entries 2401/2500.

Argued, not formalized.

  • Mechanism. With two inputs, the energy restriction forces a common ground state close to both encoded states (the companion paper’s proof). With four inputs, a partially entangled state with Schmidt coefficients 4/5 and 3/5 leaves every message marginal below the energy threshold. Meanwhile, four orthogonal sign patterns let Bob read two bits from the joint system, which no low-energy single message can carry as well.
  • Range. Take the same construction with Ψ = cos t|00⟩ + sin t|11⟩ and R the rotation by t. Each message then has vacuum component cos⁴t + sin⁴t, so ω = sin²(2t)/2, and the success is ((1 + sin 2t)/2)². It beats the bound 1/4 + √ω exactly when sin 2t > 2√2 − 2, that is for 6 − 4√2 ≈ 0.343 < ω < 1/2. The true unassisted optimum may lie below this bound, so the advantage may extend further.

Open.

  • The smallest ω at which unitary encoding helps in some task, and the optimal unitary value for four-message discrimination at each ω.
  • Whether three inputs suffice.

Effect on the paper. Result 4 does not extend to general tasks: unitary encoding of a partially entangled state is already a resource for four messages below ω = 1/2.

ASSUMED-UNVERIFIED

The bounded literature check does not establish exhaustive worldwide novelty or priority. The statements in “Computed, not formalized” and “Argued, not formalized” are not formalized.