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RESEARCH / Focused target

Optimality of the Ordered Zeckendorf Long Game Strategy

Literature status: not recheckedOur route: proposed

RELEASED FOUNDATIONS / PROPOSED CONNECTION

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Problem

The question

A state is an ordered list of Fibonacci numbers. The game starts with n copies of F_1. Legal adjacent moves are (F_i, F_{i+1}) -> F_{i+2}; (F_1, F_1) -> F_2; (F_i, F_i) -> (F_{i-2}, F_{i+1}) for i > 2; (F_2, F_2) -> (F_1, F_3); and switching an inversion (F_i, F_j) -> (F_j, F_i) when i > j.

The Long Game Strategy uses the priority: all switch moves in any order, combine adjacent ones from the left, split from the right, then merge from the left.

Conjecture 1.7, quoted from arXiv:2508.20222v2:

“The LGS has the longest game length.”

Status statement, quoted from the same version:

“The longest-game strategy described in Conjecture 1.7 is supported by empirical simulations. However, a rigorous proof establishing its optimality remains an open problem.”

Proposed formalization, after importing the five moves exactly:

∀ n, ∀ g, IsLGSRun n g ->
  Terminal g.last ∧
  ∀ h, LegalTerminalRun n h -> h.length ≤ g.length

This universal form is appropriate only if the paper's "switch moves (in any order)" is intended to give the same LGS length for every switch ordering. Otherwise use an explicit deterministic tie-breaker or an existential maximizing LGS run.

The paper says the conjecture is backed by exhaustive simulations rather than a proof. In its broader exact game-tree analysis it also states:

“Due to the combinatorial explosion in the number of game states and legal move sequences, a full resolution of the winner for n>25 was computationally infeasible.”

That second quote concerns winner computation, not directly Conjecture 1.7, but it identifies the same state-space obstacle. For length, the paper proves only upper and lower asymptotics and a structural lemma about repetitions under LGS.

Motivation

Our foothold

  • Erasing order maps a game state to RawDigits. Each merge and split move preserves Fibonacci value and is closely related to a frozen carry step; switch moves erase to the identity.
  • The frozen normalizer proves termination and unique canonical output for its own oriented carry system. This explains the shared terminal Zeckendorf state, but confluence intentionally forgets path lengths.
  • The new content is an extremal refinement of rewriting: among ordered value-preserving paths from [F_1,...,F_1] to the sorted normal form, LGS should maximize length.

Gap

Missing bridges

  • RawDigits is a multiplicity map and loses order; no ordered list state or inversion count exists.
  • Frozen carry orientation is not identical to the paper's bidirectional merge/split game.
  • Newman confluence and normal-form uniqueness say nothing about longest paths.
  • LGS contains a tie phrase "switch moves (in any order)" that must be resolved before a Lean proposition is exact.

Route

Proposed approach

  1. Define ordered index lists and the five legal moves; prove value preservation and the forgetful map to RawDigits.
  2. Port the paper's strictly decreasing monovariant to obtain a finite DAG independently of frozen normalization.
  3. Define height(S) as the longest remaining path to terminal. It satisfies a Bellman recursion on the finite DAG.
  4. Prove local exchange lemmas matching LGS priority: an inversion swap can be commuted before any non-switch without decreasing remaining height; leftmost F_1 merge dominates other merge choices; rightmost split dominates other splits.
  5. Use the paper's at-most-one-higher-index-repetition state classification to make the split exchange finite. A successful proof shows the LGS move is always an argmax successor in the Bellman recursion.
  6. Prove switch-order independence as a separate lemma; if false, tighten the conjecture to the paper's intended deterministic interpretation and record the counterexample.

Falsifier

What would falsify this route

A complete certificate consists of a smallest n, an exact legal terminal LGS run g, and another exact legal terminal run h with length h > length g. If switch ordering changes LGS length, two LGS runs with unequal lengths falsify the universal proposed formalization even if one remains globally maximal.

Evidence

Evidence to collect

Construct a memoized exact DAG for n <= 30:

  1. canonicalize states only by the ordered Fibonacci-index tuple; do not quotient by multiplicity;
  2. compute exact height(S) and retain a maximizing successor witness;
  3. enumerate every LGS tie choice and compare its length to height(start_n);
  4. emit, for each state reached by LGS, whether its chosen move is height-maximizing;
  5. when a priority exchange first fails locally, save both suffix paths even if the global conjecture still holds.

This extends the paper's simulation into proof-certificate-shaped data and directly probes the formal ambiguity.

Triage

Scope assessment

theorem. The state space is finite and terminating, and the repository has the value/carry/normal-form backbone; the likely proof is a finite family of exchange lemmas rather than a new analytic theory.

ASSUMED-UNVERIFIED

Unverified assumptions

  • All permitted switch orders in LGS have equal length, or the authors intended a deterministic completion not explicit in the quoted definition.
  • The paper's game moves correspond cleanly enough to frozen carry identities to reuse value proofs.
  • The at-most-one-repetition lemma suffices to close every local optimality branch.
  • Whether Conjecture 1.7 was resolved after arXiv v2 is unverified; novelty of the exchange-lemma route is unassessed.

Dossier & anchor history

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