Restricted Integer Maxima and the Terminal Inventory Chain
Abstract
Actual nonlinear maxima on a forced divisor domain have strict own-clock layer counts.
The objective is exactly log(sigma(n)/n)-log(log(log(n))). The prime layer marginal is the existing goldenLayerMarginal, and price(t)=1/(t*log(t)). Equal-price layers are excluded by optimalLayerCount. The core remains a positive natural integer; a real clock is never substituted for an original prime label.
Theorem 1.1 (Classification of every constrained nonlinear maximum).
Lean statement: D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.restricted_divisor_maximum_strict_inventory
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.restricted_divisor_maximum_strict_inventory (✓ std3). ∎
Source. Repository-derived.
Commentary.
Let p be prime, m and V positive, and let W be a positive multiple of m dividing V. Assume p does not divide V, log(pm)>1, and log(pV)<a. At the parent clock a, every prime’s first layer above its V exponent has marginal at most price(a). Every occupied mandatory m layer is strictly active already at log(pm). If pW maximizes the literal original objective over all positive pU with m dividing U and U dividing V, then every natural direction q has W.factorization(q) equal to optimalLayerCount(price(log(pW)),q). Nonprime directions and zero exponent stacks are included.
When a stack is below the V exponent, inserting its next layer is legal. The actual single-prime objective delta and a strict log-log tangent inequality put its marginal strictly below the own-clock price. In a saturated stack, the weak inactive bound at the larger parent clock becomes strict because the literal price decreases. A layer can be deleted only above the mandatory m floor; deleting the top occupied layer then puts its marginal strictly above the own-clock price. Mandatory layers are handled by their stated earlier-clock activation. The existing active-layer interval theorem identifies the complete strict count. No deletion of an internal prime layer is used.
Theorem 1.2 (An exact reduction of the strict divisor certificate).
Lean statement: D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.strict_5040_divisor_comparison_iff_inventory
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.strict_5040_divisor_comparison_iff_inventory (✓ std3). ∎
Source. Repository-derived.
Commentary.
Let p be prime with p<P, let V be positive, and suppose p does not divide V. Assume log(p5040)>=243 and every prime’s next layer above its V exponent is inactive at log(PV). Then pV strictly beats every pU with positive proper divisor U of V divisible by 5040 if and only if it strictly beats those same proper divisors whose exponents obey the strict inventory law at their own log(p*U). The certificate compares actual integer objective values.
The comparison family itself requires 5040 dividing every competitor U. A separate 5040-divisibility premise on V is unnecessary for this equivalence; it holds even for an empty proper-competitor family. The actual terminal application has 5040 dividing V.
If any proper divisor ties or beats V, choose a maximum over the finite proper-divisor domain. Its value also beats V, so it maximizes over the complete divisor domain. The classification theorem puts this proper maximum in the inventory family and contradicts the proposed strict comparisons. This retains exact ties without assuming a least full-domain maximizer. The mandatory 5040 activation is derived from the existing global fixed-price optimum at 1/25 and the earlier clock at least 243; its bottom layers are never deleted.
For the actual terminal source PV, a strict inventory law for V at log(PV) supplies the displayed inactive next-layer premise. Taking p to be the immediate previous complete label gives the finite certificate family used in the ordinary terminal comparison. The identity F(pV)-F(pU)=beta(U)-J(U) still requires strictly positive margins. Neither this reduction nor the classification proves those margins, a heat-scale upper gap between a_good and a_full, a fixed positive terminal reserve, the complete signed prime budget, Robin’s inequality or the Riemann hypothesis.
Theorem 1.3 (Every original maximizing tie has the residual strict inventory).
Lean statement: D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.original_maximum_strict_inventory
Proof. Machine-checked in Lean as D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.original_maximum_strict_inventory (✓ std3). ∎
Source. Repository-derived.
Commentary.
Let p be prime and let N satisfy the literal OriginalFirstClockTransport.originalMaximizes(p,N): N is positive, 5040p divides N, and N maximizes originalObjective over every positive multiple of 5040p. Assume exactly 243<=log(N)<p. Then N.factorization(p)=1, and there is a positive natural integer U with N=p*U, 5040 dividing U, p not dividing U, and U.factorization(q)=optimalLayerCount(ActualRobinClockCovariance.g(log(N)),q) for every natural q. The clock remains log(N), rather than log(U). The result applies to every maximizing tie; no least-source choice or attainment supplier is assumed.
For every prime q, Nq is again a positive multiple of 5040p. Its exact prime_delta and the existing strict loglog_tangent inequality force the next N layer strictly below the price at log(N). To delete a top q layer, its exponent must exceed the factorization of the entire mandatory floor 5040p. Factorization subtraction then proves 5040p divides N/q, so this is an actual legal competitor. Its floor also keeps log(N/q)>1. The same strict tangent, taken at log(N), forces the removed layer strictly above that same price. Weak maximality is sufficient for both strict comparisons, including objective ties.
Since p>log(N)>=243, the prime p is not a divisor of 5040, and its mandatory floor exponent is one. The existing reciprocal-power marginal bound and strict price decrease put even its first layer below the own-clock price. Strict marginal decrease therefore makes every higher p layer inactive. A p exponent at least two would permit deleting its top layer and contradict the strict deletion comparison. Hence precisely one p is removed to construct U, preserving every mandatory 5040 layer.
For q different from p, N and U have identical q exponents. Their next residual layer is strictly inactive by legal insertion into N. An occupied residual top layer above the 5040 floor is strictly active by legal deletion from N. At the floor it is active by the existing forced_5040_active argument at log(N)>=243. For q=p the residual stack is empty and its first layer is inactive. The strict active-layer interval identifies each count, including absent prime stacks. Nonprime directions have zero factorization and zero optimalLayerCount by their definitions; no prime-power stack or equality endpoint is omitted.
This bridge derives the inventory from original nonlinear maximality. It assumes no inventory law, forced exponent-one premise, fixed-price optimality, analytic supplier or MAIN upper bound. Existence of such an original maximizer and the displayed clock window remain separate obligations. The bridge alone supplies neither the JC18 initial arithmetic-height payment nor the complete signed prime budget, strict Robin inequality or RH.
Repository derivation reuses the original integer objective, the single-prime objective delta, the strict active-layer count interval and literal price monotonicity. A search of the repository, pinned Mathlib and the public Robin1984 CAProfile/CAReduction sources found fixed-price Euler thresholds and Robin reduction, but no matching constrained nonlinear divisor-maximum classification. No literature priority claim is made.
References
- Truth anchor:
D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.original_maximum_strict_inventory - Truth anchor:
D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.restricted_divisor_maximum_strict_inventory - Truth anchor:
D5/S3/Arith/Robin/RestrictedDivisorStrictInventory.strict_5040_divisor_comparison_iff_inventory - Dependency: D5/S3/Arith/Robin/OriginalFirstClockTransport